(2x+1)*(x^2+3x-4)=y

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Solution for (2x+1)*(x^2+3x-4)=y equation: 


Simplifying
(2x + 1)(x2 + 3x + -4) = y

Reorder the terms:
(1 + 2x)(x2 + 3x + -4) = y

Reorder the terms:
(1 + 2x)(-4 + 3x + x2) = y

Multiply (1 + 2x) * (-4 + 3x + x2)
(1(-4 + 3x + x2) + 2x * (-4 + 3x + x2)) = y
((-4 * 1 + 3x * 1 + x2 * 1) + 2x * (-4 + 3x + x2)) = y
((-4 + 3x + 1x2) + 2x * (-4 + 3x + x2)) = y
(-4 + 3x + 1x2 + (-4 * 2x + 3x * 2x + x2 * 2x)) = y
(-4 + 3x + 1x2 + (-8x + 6x2 + 2x3)) = y

Reorder the terms:
(-4 + 3x + -8x + 1x2 + 6x2 + 2x3) = y

Combine like terms: 3x + -8x = -5x
(-4 + -5x + 1x2 + 6x2 + 2x3) = y

Combine like terms: 1x2 + 6x2 = 7x2
(-4 + -5x + 7x2 + 2x3) = y

Solving
-4 + -5x + 7x2 + 2x3 = y

Solving for variable 'x'.

Combine like terms: y + -1y = 0
-4 + -5x + 7x2 + 2x3 + -1y = 0

The solution to this equation could not be determined.

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